## Precalculus (10th Edition)

$\sqrt{26}$.
The distance $d$ from $P_1(x_1,y_1,z_1)$ to $P_2(x_2,y_2,z_2)$ is given by the formula $d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$. Hence here $d=\sqrt{(3-4)^2+(2-(-2))^2+(1-(-2))^2}=\sqrt{(-1)^2+4^2+3^2}=\sqrt{1+16+9}=\sqrt{26}$.