Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - 9.3 The Complex Plane; De Moivre's Theorem - 9.3 Assess Your Understanding - Page 595: 72

Answer

$\dfrac{4\pi}{3}$

Work Step by Step

We know that $360^\circ=2\pi$ radians. Hence, $240^\circ=240^o \cdot \dfrac{2\pi}{360^o}=\dfrac{4\pi}{3}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.