## Precalculus (10th Edition)

approximately $40.5$ square units
By definition, the area $K$ of a triangle whose two sides and the included angle are known is given by the formula $K=\frac{ab\cdot sin(C)}{2}.$ Hence, here we have: $K=\dfrac{8\cdot11\cdot \sin(113^\circ)}{2}\approx40.5$