Answer
approximately $40.5$ square units
Work Step by Step
By definition, the area $K$ of a triangle whose two sides and the included angle are known is given by the formula $K=\frac{ab\cdot sin(C)}{2}.$
Hence, here we have:
$K=\dfrac{8\cdot11\cdot \sin(113^\circ)}{2}\approx40.5$