Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 9 - Polar Coordinates; Vectors - 9.3 The Complex Plane; De Moivre's Theorem - 9.3 Assess Your Understanding - Page 595: 71


approximately $40.5$ square units

Work Step by Step

By definition, the area $K$ of a triangle whose two sides and the included angle are known is given by the formula $K=\frac{ab\cdot sin(C)}{2}.$ Hence, here we have: $K=\dfrac{8\cdot11\cdot \sin(113^\circ)}{2}\approx40.5$
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