Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.5 Sum and Difference Formulas - 7.5 Assess Your Understanding - Page 488: 80

Answer

$\frac{33}{65}$

Work Step by Step

Step 1. Letting $tan^{-1}(\frac{5}{12})=u$, we have $tan(u)=\frac{5}{12}$, thus $sin(u)=\frac{5}{13}, cos(u)=\frac{12}{13}$ Step 2. Letting $sin^{-1}(-\frac{3}{5})=v$, we have $sin(v)=-\frac{3}{5}$, thus $cos(v)=\frac{4}{5}$ Step 3. $cos(u-v)=cos(u)cos(v)+sin(u)sin(v)=(\frac{12}{13})(\frac{4}{5})+(\frac{5}{13})(-\frac{3}{5})=\frac{48-15}{65}=\frac{33}{65}$
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