Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.5 Sum and Difference Formulas - 7.5 Assess Your Understanding - Page 488: 77

Answer

$-\frac{24}{25}$

Work Step by Step

Step 1. Letting $sin^{-1}(\frac{3}{5})=u$, we have $sin(u)=\frac{3}{5}$, thus $cos(u)=\frac{4}{5}$ Step 2. Letting $cos^{-1}(-\frac{4}{5})=v$, we have $cos(v)=-\frac{4}{5}$, thus $sin(v)=\frac{3}{5}$ Step 3. $sin(u-v)=sin(u)cos(v)-cos(u)sin(v)=(\frac{3}{5})(-\frac{4}{5})-(\frac{4}{5})(\frac{3}{5})=-\frac{12+12}{25}=-\frac{24}{25}$
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