Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.5 Sum and Difference Formulas - 7.5 Assess Your Understanding - Page 487: 34

Answer

$\dfrac{\sqrt3}{2}$

Work Step by Step

Recall that: $\sin(\alpha+\beta)=\sin(\alpha)\cos(\beta)+\cos(\alpha)\sin(\beta)$ Hence, $\sin(\frac{\pi}{18})\cos(\frac{5\pi}{18})+\cos(\frac{\pi}{18})\sin(\frac{5\pi}{18})\\ =\sin\left(\frac{5\pi}{18}+\frac{\pi}{18}\right)\\ =\sin(\frac{\pi}{3})\\ =\frac{\sqrt3}{2}$
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