Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.5 Sum and Difference Formulas - 7.5 Assess Your Understanding - Page 487: 3


a)$\frac{\sqrt2}{4}$ b)$\frac{1}{2}$

Work Step by Step

a) $\sin{\frac{\pi}{4}}\cos{\frac{\pi}{3}}=\frac{\sqrt2}{2}\frac{1}{2}=\frac{\sqrt2}{4}$ b) $\tan{\frac{\pi}{4}}-\sin{\frac{\pi}{6}}=1-\frac{1}{2}=\frac{1}{2}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.