Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.5 Sum and Difference Formulas - 7.5 Assess Your Understanding - Page 487: 32

Answer

$-1$

Work Step by Step

Recall that: $\cos(\alpha+\beta)=\cos(\alpha)\cos(\beta)-\sin(\alpha)\sin(\beta)$ Hence, $\cos(\frac{5\pi}{12})\cos(\frac{7\pi}{12})-\sin(\frac{5\pi}{12})\sin(\frac{7\pi}{12})=\cos\left(\frac{5\pi}{12}+\frac{7\pi}{12}\right)=\cos(\pi)=-1$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.