Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 7 - Analytic Trigonometry - 7.3 Trigonometric Equations - 7.3 Assess Your Understanding - Page 467: 82

Answer

$\frac{\pi}{2}$

Work Step by Step

Rewrite the equation $\frac{1}{cos\theta}=\frac{sin\theta}{cos\theta}+\frac{cos\theta}{sin\theta} \longrightarrow sin\theta=sin^2\theta+cos^2\theta=1$. Thus $\theta=\frac{\pi}{2}$
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