Answer
$\frac{\pi}{2}$
Work Step by Step
Step 1. Factor the equation $ (2sin\theta-3)(sin\theta-1)=0$. Thus $sin\theta=1$ or $sin\theta=\frac{3}{2}$.
Step 2. For $sin\theta=1$, we have $\theta=\frac{\pi}{2}$
Step 3. For $sin\theta=\frac{3}{2}$, we have $\theta=none$
