Answer
$0,\pi,\frac{\pi}{3},\frac{5\pi}{3}$
Work Step by Step
Step 1. Rewrite the equation $\frac{sin\theta}{cos\theta}=2sin\theta$. Thus $sin\theta=0$ or $cos\theta=\frac{1}{2}$
Step 2. For $sin\theta=0$, we have $\theta=0,\pi$
Step 2. For $cos\theta=\frac{1}{2}$, we have $\theta=\frac{\pi}{3},\frac{5\pi}{3}$
