Answer
$-\frac{3\pi}{4}, \frac{\pi}{4}, \frac{5\pi}{4}, \frac{9\pi}{4} $
Work Step by Step
Let $tan(x)=1$, we can find a general form of the solutions as $x=k\pi+\frac{\pi}{4}$ where $k$ is an integer. For $k=-1,0,1,2$, we have $x=-\frac{3\pi}{4}, \frac{\pi}{4}, \frac{5\pi}{4}, \frac{9\pi}{4} $
