Answer
$2x-5+h$
Work Step by Step
Step 1. Given $f(x)=x^2-5x+1$, we have $f(x+h)=(x+h)^2-5(x+h)+1=x^2+2xh+h^2-5x-5h+1$
Step 2. We have $f(x+h)-f(x)=x^2+2xh+h^2=5x-5h+1-(x^2-5x+1)=2xh+h^2-5h$
Step 3. Thus $\frac{f(x+h)-f(x)}{h}=2x-5+h$
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