Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.4 Graphs of the Sine and Cosine Functions - 6.4 Assess Your Understanding - Page 411: 104

Answer

$(2,5)$

Work Step by Step

$g(x)=-3x^2+12x-7=-3(x^2-4x+4)+12-7=-3(x-2)^2+5$. Thus the vertex is at $(2,5)$
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