Answer
amplitude: $\frac{5}{3}$
period: $3$
Work Step by Step
If a function has form $y=A\sin(\omega x)$, then there $|A|$ stands for the amplitude.
First we identify $\omega$ and $A$ from the form of $y=A\sin{(\omega x)}$.
Hence, $A=\left|\frac{5}{3}\right|=\frac{5}{3}$, $\omega=\frac{-2\pi}{3}.$
To get the period $T$ we can use the formula $T=\left|\frac{2\pi}{\omega}\right|$ to obtain
$T=\left|\dfrac{2\pi}{\frac{-2\pi}{3}}\right|=3$