Answer
amplitude: $1$
period: $4\pi$
Work Step by Step
If a function has form $y=A\sin(\omega x)$, then there $|A|$ stands for the amplitude.
First we identify $\omega$ and $A$ from the form of $y=A\sin{(\omega x)}$.
Hence, $A=|-1|=1$, $\omega=0.5.$
To get the period $T$ we can use the formula $T=\frac{2\pi}{\omega}$ to obtain
$T=\frac{2\pi}{0.5}=4\pi$