Answer
amplitude: $\frac{4}{3}$
period: $3\pi$
Work Step by Step
If a function has form $y=A\sin(\omega x)$, then there $|A|$ stands for the amplitude.
First we identify $\omega$ and $A$ from the form of $y=A\sin{(\omega x)}$.
Hence, $A=\left|\frac{4}{3}\right|=\frac{4}{3}$, $\omega=\frac{2}{3}.$
To get the period $T$ we can use the formula $T=\frac{2\pi}{\omega}$ to obtain
$T=\dfrac{2\pi}{\frac{2}{3}}=3\pi$
