Answer
False.
Work Step by Step
If a function has form $y=A\sin(\omega x)$, then there $|A|$ stands for the amplitude.
First we identify $\omega$ and $A$ from the form of $y=A\sin(\omega x)$.
Hence, $A=2$, $\omega=\pi.$
The amplitude is $|A|=|2|=2$.
To get the period $T$ we can use the formula $T=\frac{2\pi}{\omega}$ to obtain
$T=\frac{2\pi}{\pi}=2\ne\frac{\pi}{2}$, hence the given statement is false.
