Answer
$A=3$,$\omega=\frac{\pi}{3}.$
Work Step by Step
If a function has form $y=A\cos(\omega x)$, then there $|A|$ stands for the amplitude.
First we identify $\omega$ and $A$ from the form of $y=A\cos(\omega x)$.
Hence, $A=3$, $\omega=6.$ The amplitude is $|A|=|2|=2$.
To get the period $T$ we can use the formula $T=\frac{2\pi}{\omega}$ to obtain $T=\frac{2\pi}{6}=\frac{\pi}{3}$.
