Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.4 Graphs of the Sine and Cosine Functions - 6.4 Assess Your Understanding - Page 407: 4

Answer

$A=3$,$\omega=\pi.$

Work Step by Step

$A=3$ (because $|A|$ stands for the amplitude), $T=\frac{2\pi}{\omega}=\frac{2\pi}{2}=\pi.$ (because $T=\frac{2\pi}{\omega}$ indicates the period)
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