Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 380: 113

Answer

$\dfrac{\sqrt2}{4}$

Work Step by Step

RECALL: $(f \circ h)(x)=f\left(h(x)\right)$ Use the rule above to obtain: $(p\circ g)(315^\circ)=p\left(g(315^\circ)\right)=p(\cos{315^\circ})=p\left(\dfrac{\sqrt2}{2}\right)=\dfrac{\frac{\sqrt2}{2}}{2}=\dfrac{\sqrt2}{4}$
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