Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 380: 107

Answer

$\dfrac{1+\sqrt3}{2}$

Work Step by Step

RECALL: $(f+g)(x)=f(x)+g(x)$ Use the rule above to obtain: $(f+g)(30^\circ)=\sin{30^o}+\cos{30^o}=\dfrac{1}{2}+\dfrac{\sqrt3}{2}=\dfrac{1+\sqrt3}{2}$
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