Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 380: 112

Answer

$\dfrac{\sqrt3}{2}$

Work Step by Step

RECALL: $(f \circ h)(x)=f\left(h(x)\right)$ Use the rule above to obtain: $(g\circ p)(60^\circ)=g\left(p(60^\circ)\right)=g\left(\dfrac{60^\circ}{2}\right)=g(30^\circ)=\cos{30^\circ}=\dfrac{\sqrt3}{2}$
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