Answer
$\frac{1}{60}\ rad/sec$, $ \frac{1}{12}\ cm/s$
Work Step by Step
Given $r=5cm, 20sec\rightarrow \frac{1}{3} rad$, we have the angular speed $\omega=\frac{1}{3}\div20=\frac{1}{60}\ rad/sec$. We can find the linear speed as $v=\omega r=\frac{1}{60}\times5=\frac{1}{12}\ cm/s$
