Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.1 Angles and Their Measure - 6.1 Assess Your Understanding - Page 363: 110

Answer

$794.16$mph.

Work Step by Step

The distance from the axis is: $r=3033.5$ miles. The Earth takes $24$ hours to make a revolution, hence its angular velocity is: $\omega=\frac{2\pi}{t}=\frac{2\pi}{24}=0.2618\frac{\text{rad}}{\text{hr}}.$ Therefore the linear velocity at $40^\circ$: $v=\omega r\\v=0.2618(3033.5)=794.16\text{mph}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.