Answer
$\frac{1}{8}\ rad/sec$, $\frac{1}{4}\ m/s$
Work Step by Step
Given $r=2m, t=20sec\rightarrow s=5m$, we have the angle traveled as $\theta=\frac{s}{r}=\frac{5}{2}$ and the angular speed $\omega=\frac{5}{2}\div20=\frac{1}{8}\ rad/sec$. We can find the linear speed as $v=\omega r=\frac{1}{8}\times2=\frac{1}{4}\ m/s$
