Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.1 Angles and Their Measure - 6.1 Assess Your Understanding - Page 362: 29

Answer

$40^{\circ}19'12''$

Work Step by Step

We know that $1^o = 60’$ $1’=60"$. Use a calculator and the conversion factors above to obtain: $40.32^{\circ}\\=40^{\circ}+0.32\cdot60'\\=40^{\circ}+19.2'\\=40^{\circ}+19'+0.2\cdot60''\\=40^{\circ}+19'+12''$
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