## Precalculus (10th Edition)

$\approx 98.38°$
There are $60$ seconds in $1$minute. Hence $45"=\frac{45}{60}'=0.75'$ Hence $98°22'45"=98°(22+0.75)'$ $=98°22.75'$ There are $60$ minutes in $1$ degree. Hence $22.75'=\frac{22.75}{60}°\approx0.379°$ Hence $98°22'45"\approx (98+0.379°)°$ $\approx 98.38°$ (to two decimal places)