Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.1 Angles and Their Measure - 6.1 Assess Your Understanding - Page 361: 27


$\approx 9.15°$

Work Step by Step

There are $60$ seconds in $1$minute. Hence $9"=\frac{9}{60}'=0.15'$ Hence $9°9'9"=9°(9+0.15)'$ $=9°9.15'$ There are $60$ minutes in $1$ degree. Hence $9.15'=\frac{9.15}{60}°=0.1525°$ Hence $9°9'9"=(9+0.1525)°$ $\approx 9.15°$ (to two decimal places)
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