Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.1 Angles and Their Measure - 6.1 Assess Your Understanding - Page 362: 87

Answer

$2.094\ ft $, $2.094\ ft^2$

Work Step by Step

Step 1. Based on the given figure, $r=2\ ft, \theta=\frac{\pi}{3}$, we have $s=r \theta=2(\frac{\pi}{3})=(\frac{2\pi}{3})\approx2.094\ ft $ Step 2. For the area, we have $A=\frac{1}{2}r^2\theta=\frac{1}{2}(2^2)(\frac{\pi}{3})=(\frac{2\pi}{3})\approx2.094\ ft^2$
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