Answer
$5$
Work Step by Step
We know that by definition if $y=a^x$, then $log_a {y}=x$. Also $log_e {x}=ln {x}$,
and $\log_a{xy}=\log_a{x} +\log_a{y}$ hence if $y=e^x$, then $ln{e^x}=x\cdot log_e {e}=x$. Therefore if $ln {e^x}=5$, then $x=5.$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.4 Logarithmic Functions - 5.4 Assess Your Understanding - Page 296: 95
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