Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.4 Logarithmic Functions - 5.4 Assess Your Understanding - Page 296: 102



Work Step by Step

If $e^{-2x}=\frac{1}{3}$, then by taking the natural logarithm of both sides we get $-2x=ln{\frac{1}{3}}$, therefore $x=\frac{ln{\frac{1}{3}}}{-2}=\frac{-ln{3}}{-2}=\frac{ln{3}}{2}$.
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