Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.4 Logarithmic Functions - 5.4 Assess Your Understanding - Page 296: 108



Work Step by Step

We know that by definition then $log_a {y}=x$, then $y=a^x$. Hence if $log_3 {(3^x)}=-1$, then $3^{-1}=\frac{1}{3}=3^x$, therefore because the base is the same on the two sides of the equation, the exponents must be equal too, hence $x=-1$.
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