Answer
See explanations.
Work Step by Step
Step 1. As $f$ and $g$ are odd, we have $f(-x)=-f(x)$ and $g(-x)=-g(x)$
Step 2. $f\circ g=f(g(x))$ and $f(g(-x))=f(-g(x))=-f(g(x))$ thus $f\circ g$ is also odd.
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