Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 256: 66


$\frac{2}{3}\pi r^3$

Work Step by Step

We know that $V=\frac{1}{3}\pi r^2 h$ and that $h=2r$ because the height is twice the radius. Therefore $V=\frac{1}{3}\pi r^2 h=\frac{1}{3}\pi r^2 (2r)=\frac{2}{3}\pi r^3$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.