## Precalculus (10th Edition)

Published by Pearson

# Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 256: 66

#### Answer

$\frac{2}{3}\pi r^3$

#### Work Step by Step

We know that $V=\frac{1}{3}\pi r^2 h$ and that $h=2r$ because the height is twice the radius. Therefore $V=\frac{1}{3}\pi r^2 h=\frac{1}{3}\pi r^2 (2r)=\frac{2}{3}\pi r^3$

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