Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.1 Composite Functions - 5.1 Assess Your Understanding - Page 256: 64

Answer

$\frac{\sqrt {1000-5p}}{10}+400$

Work Step by Step

$p=-\frac{1}{5}x+200\\p+\frac{1}{5}x=200\\\frac{1}{5}x=200-p\\x=1000-5p$ Hence $C(x)=\frac{\sqrt x}{10}+400=\frac{\sqrt {1000-5p}}{10}+400$
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