Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 4 - Polynomial and Rational Functions - Chapter Review - Cumulative Review - Page 245: 8

Answer

$\{0,2,4 \}$

Work Step by Step

Step 1. Factor the equation to get $x(x^2-6x+8)=0\longrightarrow x(x-2)(x-4)=0$ Step 2. Thus we have the solution set $\{0,2,4 \}$
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