Answer
$(-2,1)$, $r=3$.
See graph.
Work Step by Step
Step 1. Form squares to get $(x^2+4x+4)+(y^2-2y+1)=4+4+1\longrightarrow (x+2)^2+(y-1)^2=9$
Step 2. We can identify the center as $(-2,1)$ and radius $r=3$.
Step 3. See graph.
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