Answer
$x=-1\pm i$
Work Step by Step
We can get the zeros by solving the equation $x^2+2x+2=0.$
By completing the square: $(x^2+2x+1)+1=0\\(x+1)^2+1=0\\(x+1)^2=-1$,.
Hence after taking the square root of both sides: $(x+1)=\pm i\\x=-1\pm i.$