Chapter 4 - Polynomial and Rational Functions - 4.6 Complex Zeros; Fundamental Theorem of Algebra - 4.6 Assess Your Understanding - Page 240: 1

Sum:$3i$, product:$1+21i.$

The sum generally: $(a+bi)+(c+di)=(a+c)+(b+d)i.$ Sum: $(3-2i)+(-3+5i)=(3+(-3))+i(-2+5)=3i $ The product generally: $(a+bi)\cdot(c+di)=ac+adi+bci-bd=(ac-bd)+(bc+ad)i.$ Product: $(3-2i)(-3+5i)=3(-3)+3(5)i+(-2)i(-3)-(-2)5=-9+15i+6i+10=1+21i$