Answer
$f(x)=x^3-12x-16$
Work Step by Step
If $c$ is a zero of a function with multiplicity $b$ then $(x-c)^b$ is a “factor” of the function.
We are given that the degree is $3$, and the zeros are $-2$ (multiplicity 2) and $4$ (multiplicity 1), hence
$f(x)=a(x+2)^2(x-4)\\
f(x)=a(x^3-12x-16)$
If $a=1$, the function becomes
$f(x)=x^3-12x-16$