Answer
$f(x)=x^3-x^2-12x$
Work Step by Step
If $c$ is a zero of a function with multiplicity $b$ then $(x-c)^b$ is a “factor” of the function.
We are given that the degree is $3$, and the zeros are $-3$, $0$ and $4$, hence
$f(x)=a(x+3)(x)(x-4)=a(x^3-x^2-12x)$
If $a=1$, the function is
$f(x)=x^3-x^2-12x$