Answer
$f(x)=x^3-3x^2-x+3$
Work Step by Step
If $c$ is a zero of a function with multiplicity $b$ then $(x-c)^b$ is a “factor” of the function.
We are given that the degree is $3$, and the zeros are $-1$, $1$ and $3$, hence
$f(x)=a(x+1)(x-1)(x-3)\\
f(x)
=a(x^3-3x^2-x+3)$
When $a=1$, the function is
$f(x)=x^3-3x^2-x+3$