Answer
$(\pm4,0)$, $(0,-12)$.
Work Step by Step
Step 1. To find the x-intercepts of the graph $3x^2-4y=48$, let $y=0$, we have $3x^2=48$, thus $x=\pm4$ or $(\pm4,0)$.
Step 2. To find the y-intercepts of the graph $3x^2-4y=48$, let $x=0$, we have $-4y=48$, thus $y=-12$ or $(0,-12)$.