Answer
$(x+6)^2+y^2=7$
Work Step by Step
The standard equation for a circle with radius $r$ and centre $(h,k)$ is:
$$(x-h)^2+(y-k)^2=r^2$$
Hence, for the given circle, the equation is:
$(x+6)^2+(y-0)^2=(\sqrt7)^2\\(x+6)^2+y^2=7$.
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