Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - 3.4 Build Quadratic Models from Verbal Descriptions and from Data - 3.4 Assess Your Understanding - Page 157: 34

Answer

$(x+6)^2+y^2=7$

Work Step by Step

The standard equation for a circle with radius $r$ and centre $(h,k)$ is: $$(x-h)^2+(y-k)^2=r^2$$ Hence, for the given circle, the equation is: $(x+6)^2+(y-0)^2=(\sqrt7)^2\\(x+6)^2+y^2=7$.
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