Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.5 Graphing Techniques: Transformations - 2.5 Assess Your Understanding - Page 103: 33

Answer

(a).

Work Step by Step

If $(1,3)$ is on $y=f(x)$, then on $y=2f(x)$ $3=2\cdot f(1)\\\frac{3}{2}=f(1)$. $(1,frac{3}{2})$ will be on the graph. Hence the answer is (a).
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