## Precalculus (10th Edition)

$x\lt-1$ Refer to the step-by-step part above for the graph.
Solve the inequality to obtain: $3-2x\gt5\\ (3-2x)-3\gt5-3\\ -2x\gt2$ Divide both sides by $-2$. Note that the inequality symbol will change to tis opposite direction since a negative number was divided to both sides of the inequality. $\frac{-2x}{-2} \lt \frac{2}{-2}\\ x\lt-1$ Refer to the graph below,