## Precalculus (10th Edition)

$21.5$
Substitute $-2$ to $x$ to obtain: $3(-2)^2-5(-2)+\frac{1}{-2}$ First, you must solve the operations with an exponent different from 1, which is $(-2)² = 4$ $3\times(4)-5\times(-2)+\frac{1}{-2}$ Then, you can find its products and quotient before you solve the addition The product of two positive numbers is a positive number $3\times4 = 12$ The product of two negative numbers is a positive number $(-5)\times(-2) = 10$ The quotient of a positive and a negative number is negative $\frac{1}{-2} = -0.5$ The total value of the expression is: $=12+10-0.5 \\= 21.5$