Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 56: 2



Work Step by Step

Substitute $-2$ to $x$ to obtain: $3(-2)^2-5(-2)+\frac{1}{-2}$ First, you must solve the operations with an exponent different from 1, which is $(-2)² = 4$ $3\times(4)-5\times(-2)+\frac{1}{-2}$ Then, you can find its products and quotient before you solve the addition The product of two positive numbers is a positive number $3\times4 = 12$ The product of two negative numbers is a positive number $(-5)\times(-2) = 10$ The quotient of a positive and a negative number is negative $\frac{1}{-2} = -0.5$ The total value of the expression is: $=12+10-0.5 \\= 21.5$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.