Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 56: 14


False. The domain would be all real numbers except for $0$

Work Step by Step

The negative and positive $2$ would be the correct domain if the the numerator were the denominator. But the only thing that makes a function undefined is if the denominator is 0. Since the denominator is $x$ the only value that would make it undefined is $0$ itself.
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