Answer
$\frac{6}{7}$
Work Step by Step
Factor each polynomial:
$$\lim_{x\to -3}\frac{x^2-9}{x^2-x-12}\\=\lim_{x\to -3}\frac{(x+3)(x-3)}{(x-4)(x+3)}.$$
Cancel the common factors: $$\lim_{x\to -3}\frac{x-3}{x-4}\\=\frac{(-3)-3}{(-3)-4}\\=\frac{6}{7}$$